The ribonucleotides C and G were mixed together with C 2X more abundant than G.

Question

The ribonucleotides C and G were mixed together with C 2X more abundant than G. The resulting RNAs were translated in a cell free system.

A. Give the amino acids and the relative percentages of each that would be found after the translation. Show all reasoning/calculations.

B. Suppose that di-ribonucleotides (GC) were used to make RNA and then translated in vitro. What would the results be – explain all reasoning and explain how this information could be combined with the information in part A above to try to deduce the genetic code, assuming you didn’t already know it.

Explanation / Answer

A) If there is 1part GDP, then there will be three (1+2) parts of CDP as C is 2x more abandunt than G.

Possible Composition Probability of triplet occurence Possible triplet Conc.

3G (1/4)3 = 1.56%. GGG (Glycine) 1.56

1C:2G (3/4) (1/4)2 = 4.68% CGG (Arg), GGC (Gly), GCG(Ala) 4.68 each

2C:1G (3/4)2 (1/4) = 14.06% GCC(Ala),CCG(Pro),CGC(Arg) 14.06 each

3C (3/4)3 = 42.18% CCC(Pro) 42.18

Total conc. Gly =6.24 Arg =18.74 Ala =18.74 Pro =56.24

B) Dinucleotide Polynucleotide Repeat triplets

GC GCGCGCGCGCGCGCGGCGCG GCG (Ala) and CGC(Arg)

The translated strand of amino acids should contain polymer of ala-arg-ala-arg-ala-arg-ala-arg-----

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