5. A man has an K-linked recessive form of pattern baldness. From which parent d

Question

5. A man has an K-linked recessive form of pattern baldness. From which parent did he inherit this condition. Explain your answer.M Why do individuals who inherit an A type allele and a B type allele have blood type AB while a person who inherits an A type allele and an O type allele have blood type A? bO Aandare dominan 6. How are pedigrees useful in counseling couples regarding the likelihood they can pass a genetic disorder on to their offspring? 7. A female child has the autosomal dominant condition of polydactyly. The mother has the normal number of fingers and toes while the father has six fingers on each hand. The couple has a second child, a boy, who has the normal number of fingers and toes. Give the genotype of each parent and each child 8. Parent #1 Female Child Parent #2 Male Child Draw a pedigree demonstrating polydactyly in the above family. What is the likely hood that if they have a third child they will be born with polydactyly? 9. 12

Explanation / Answer

Since nothing has been mentioned ,as which question in particular has to be solved , so i will try to answer as many as i will be able to :

answer to question 5:

since the man has an x LINKED recessive disease,now as we know males have two different sex chromosomes unlike females and that is XY, where X always comes from the mother and Y from the father , so this explains that this man has inherited the pattern baldness from his MOTHER only.

answer to question 6:

A ,B,O are alleles for blood grouping , and it show one of the common example of  CO-DOMINANCE ,that is if A and B are both present , and since both are dominant , both will show its traits , and thus the blood group is AB, but when the person is inherited with A and O, and A is dominant to O ,and O is recessive so the person has blood group A.

answer to question 7:

pedigree help us to identify the pattern of inheritance that the disease is following, which further help us to analyse the amount of risk , that the disease can be passed to the offspring or not, it can also put light on the fact that how much is is the probability by which the boy or girl child will be affected.

answer to question 8:

now since it is given that this disease isautosomal dominant, that means it is not sex linked and second even a single allele is enough to cause the disease ,

also given is,

father -is affected

mother - is not affected.

first female child affected

male child -not affected.

now since it is not a sex linked disease, it does not depend on the sex of the child,

so simple , father (parent #1) is heterozygous = Pp (P = dominant allele and diseased allele, p is recessive)

and mother (second parent#2) is homozygous =pp ( both recessive that means not affected).

now first female child genotype ( since she is affected)= Pp( P from father (affected dominant allele, and p from mother )

and male child ( not affected , normal) = pp ( unaffected , one p from mother and another p from father , but which p is from which parent cant be easily found).

question 9: pedigree which has already been drawn there is correct , just mentioning of genotypes with each individual will be more correct), the pedigree here shows that the third child will have a 50% probability to be affected and not affected with polydactyly.

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