enarticular species of pet bird, gray feathers are dominant to green feathers. Y
ID: 148519 • Letter: E
Question
enarticular species of pet bird, gray feathers are dominant to green feathers. You have two bireen-feathered mother that came from a long line of green-feathered birds, and a gray u are interested in breeding for your pet store. Your green-feathered male's parents were a g feathered father that came from a long line of gray-feathered birds. Your gray-feathered female's parents both had green feathers. a. What percent of their offspring will have gray feathers (5 pts)? b. The female's parents produce a new clutch of eggs. What percent of the female's siblings do you expect to have green feathers (5 pts)? c. This species of bird also varies in their beak length. Long beaks are recessive to short beaks. For whatever reason, short beaks are very fashionable this year, and command a higher price for your pet store. You would like to know how many short-beaked offspring the birds you are breeding above are likely to produce. They both have long beaks. The male's parents both had short beaks, while the female's father had a short beak, and her mother had a long beak. What percent of their offspring will have short beaks? (5 pts) d. While short beaks are more fashionable, green-feathered long-beaked birds also command a high price. What percent of your cross will have this valuable set of traits? (5 pts)Explanation / Answer
Gray feathers = Dominant = G
Green feathers = Recessive = g
Genotype of the male = gg
Genotype of the female = GG/Gg
There is a problem/mistake with the given question.
Since green feathers is recessive trait, two parents with green feathers will produce only green progeny. They cannot produce gray progeny.
gg X gg ----> gg
a. gg X GG ---> Gg (100% gray feathers)
gg X Gg ---> Gg gg (50% gray and 50% green)
b. Females parents: gg X gg ---> gg (100% green)
c. Short beaks = Dominant = S
Long beaks = Recessive = s
Genotype of the male = SS/Ss
Genotype of the female = Ss
SS X Ss ---> SS Ss (50% long and 50% short)
Ss X Ss ----> SS Ss Ss ss (3:1 Short:long)
d. In the above cross, only 1/4th progeny will exhibit green-feathers and long beak.
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