The density of a 6 foot tall man that weighs 840. Newtons fluctuates from a valu

Question

The density of a 6 foot tall man that weighs 840. Newtons fluctuates from a value slightly less than the density of water when the man completely inhales to a value slightly more than the density of water when the man completely exhales.

Note: Assume that the water pressure does not affect the volume of the man.

1.) The man completely exhales and jumps into the deep end of a pool with a depth of 9 feet. The man sinks to the bottom of a pool and lands on a scale; at equilibrium, the scale reads 44.5 Newtons.

A. Calculate the buoyant force of the water acting on the man with his breath completely exhaled.

Hint: Use the following partial solution to assist in the complete solution.

Note: Enumerate all force terms on the summation side of Newton's Second Law.

Hint:   The man experiences a normal force from the pool bottom.

B. Calculate the volume of the man with his breath completely exhaled.

Hint:   The volume of the man with his breath completely exhaled is 0.08m3to one significant digit; the correct answer must include three significant digits.

Explanation / Answer

part A

acording to question sum of force acting on upward direction means in Y axis =0N

so

weight of men = buoyant force of water + scale reading

buoyant force of water=840-44.5=795.5N= weight of water displacement

part b

displace mass=density of water * volume

(795.5/9.8)=998.2 *V

V=.0813198 m3

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