The power output of a star is 8.2 * 10^26 watts. Determine the intensity of the

Question

The power output of a star is 8.2 * 10^26 watts. Determine the intensity of the star's radiation on a planet at a distance of 2.50 x 10^11 meter from the star. 2805 watts/meters^2 1045 watts/meters^2 403 watts/meters^2 110 watts/meters^2 Answer A swimmer heading directly across a river 3000 meter wide reaches the opposite side of the river at a point 1800 meters downstream. The time required for the trip was 1500 seconds. If the water was flowing directly down stream, then determine the speed of the water (relative to the ground) during this entire motion. 2.00 meter/second 0.70 meter/second 1.20 meter/second 1.50 meter/second Answer Assume that a planet's orbit around a star is circular and that the time required for one complete orbit is 8770 hours. Calculate the distance that the planet travels in 4200 hours. (The distance from the planet to the star is 2.5 X 10^11 meters.) 1.05 x 10^12 meters 8.59x 10^11 meters 1.36 x 10^12 meters 7.52 x 10^11 meters Answer

Explanation / Answer

7. Intensity I = power/area

I = 8.2 e 26/(4*3.14 * 2.5 e 11 * 2.5 e 11)

I = 1045 W/m^2 option B

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8. Velocity V = Displacement/time

V = 1800/1500

V = 1.2 m/.s option C

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9 appy from Keplers third law

T^2 = R^3

(R2/R1)^3 = (T2/T1)^2

option A it is 1.05 e 12 m

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