the power output of the sun is 3.9x10^26 watts. determine the intensity of the s

Question

the power output of the sun is 3.9x10^26 watts. determine the intensity of the sun's radiation that is incident on the top of the atmosphere of the planet Earth. The distance from the sun to Earth is 1.50x10^11 meters. the power output of the sun is 3.9x10^26 watts. determine the intensity of the sun's radiation that is incident on the top of the atmosphere of the planet Earth. The distance from the sun to Earth is 1.50x10^11 meters. the power output of the sun is 3.9x10^26 watts. determine the intensity of the sun's radiation that is incident on the top of the atmosphere of the planet Earth. The distance from the sun to Earth is 1.50x10^11 meters.

Explanation / Answer

Given,

I = 3.9 x 1026 W ; R = 1.5 x 1011 m

We need to determine the intensity of Sun's radiation on the top of Earth's atmospeher.

The intensity will be evenly distributed over the area of sphere with the given distance as radius.

A = 4 pi R2 = 4 x 3.14 x (1.5 x 1011 m)2 = 2.826 x 1023 m2

we know from the defination of intensity:

I = P/A

I = 3.9 x 1026 W / 2.826 x 1023 m2 = 1.38 x 103 W/m2 = 1380 W/m2

Hence, Intensity = I = 1380 W/m2

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