A bucket of water is connected to a helicopter by a rope. The rope pulls with a

Question

A bucket of water is connected to a helicopter by a rope. The rope pulls with a force of 1000 N at an angle of 25 degrees to the right of vertically upward. Gravity pulls vertically downward on the bucket with a force of 750 N. Air resistance exerts a force of 350 N.

What are the x and y components of the force on the rope on the bucket?

What are the x and y components of the force of gravity on the bucket?

What are the x and y componentns of the force of air on the bucket?

What are the x and y components of the total force acting on the bucket?

Explanation / Answer

a)
x component of force on rope= 1000*sin 25 = 422.62 N
y component of force on rope= 1000*cos 25 = 906.31 N

b)
x component of gravity on rope= 0 N
y component of gravity on rope= -750 N

c)
x component of air on rope= 0 N
y component of air on rope= -350 N

d)
b)
x component of net force = 422.62 + 0 + 0 = 422.62 N
y component of net force = 906.31 -750 -350 = -193.69 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.