An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree

Question

An ice cube of mass 50.0 g can slide without friction up and down a 25.0 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 0.100 m . The spring constant is 25.0 N/m . When the ice cube is released, how far will it travel up the slope before reversing direction?

Identify the initial and final gravitational potential energies.

Enter your answers, separated by a comma, in terms of some or all of the variables m, k, x, d, , and the acceleration due to gravity, g.

Identify the initial and final elastic potential energies.

Enter your answers, separated by a comma, in terms of some or all of the variables m, k, x, d, , and the acceleration due to gravity, g.

Explanation / Answer

here,

mass of the cube , m = 0.05 kg

angle , theta = 25 degree

compression in the spring , x = 0.1 m

spring constant , k = 25 N/m

let it travel d distance up the slope,

using conservation of energy

0.5 * k * x^2 = m * g * d * sin(theta)

0.5 * 25 * 0.1^2 = 0.05 * 9.8 * d*sin(25)

d = 0.6 m

the distancxe travelled up the incline is 0.6 m

taken base of the incline be zero level

the initial gravitational potential energy is zero

the final gravitational potential energy is m*g*d*sin(theta)

the initial elastic potential energy , E = 0.5 * k *x^2

the final elastic potential energy is 0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.