You throw a stone vertically upward from the roof of n building with a velocity

Question

You throw a stone vertically upward from the roof of n building with a velocity of 47 m/s and lands the ground after 11.9 sec. What is the height of the building? Assume g = 10 m/s^2. A 10 N force has an angle of o degree with x avis and another force 5 N has an angle of 60 degree with x axis. If you want to add these sectors what is the total x component? You drive 5 miles in 5 min to east, then 20 miles in 20 min to south. 3 miles in 3 min in west and finally 5 miles in 5 min to the north to reach the school What is the average velocity in this trip? You throw a stone vertically upward from the roof of an 49 m tall building with a velocity of 45 m/s- How long after the stone will Land the ground? [Assume g = 10 m/s2) You throw a stone vertically upward from the roof of an 80 m tall building with a velocity of 50 m/s. At what velocity, the stone will hit the ground? [Assume g = 10 m/s2]

Explanation / Answer

Q8) Taking upward direction as positive. Let h be the height of the building. The stone starts at the top of the building and finally lands on the ground, so displacement = - h ( - sign because displacement is downwards)

u = 47m/s; t = 11.9 s ; a = -10 m/s2  ( gravity acts downwards)

s = ut + 1/2 a t2

-h = 47*11.9 - 1/2 * 10 * 11.92

h = 148.75m

Q9) 10 N force is along x axis so its x compnent = 10N

x component of 5 N force = 5 cos 60 = 2.5 N

Total x component = 10+2.5 = 12.5 N

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