A warehouse worker is pushing a 90.0-kg crate with a horizontal force of 280 N a

Question

A warehouse worker is pushing a 90.0-kg crate with a horizontal force of 280 N at a speed of v = 0.870 m/s across the warehouse floor. He encounters a rough horizontal section of the floor that is 0.75 m long and where the coefficient of kinetic friction between the crate and floor is 0.351.

(a) Determine the magnitude and direction of the net force acting on the crate while it is pushed over the rough section of the floor.

magnitude

(b) Determine the net work done on the crate while it is pushed over the rough section of the floor.

(c) Find the speed of the crate when it reaches the end of the rough surface.

Explanation / Answer

a) net force = 280 - (0.351*90*9.81) = -29.582 N
acceleration = -29.582/90 = -0.328m/s²
b) Net work = -29.582*0.75 = -22.1856 J

c) v2 = u2 +2as
    v2 =(0.87)2 -2*0.328*0.75

v =0.514 m/s

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