y(x,t) = A sin(2 pi x/lambda 2 pi ft + phi) The wave is propagating in the posit
ID: 1481755 • Letter: Y
Question
y(x,t) = A sin(2 pi x/lambda 2 pi ft + phi) The wave is propagating in the positive x direction. The displacement as a function of time is shown in the graphs below for two positions, x = 0 m and x = 0.03 m. Find the values for the following quantities consistent with the functions shown in the graphs. The amplitude: A = The frequency: f = In order to calculate the wavelength, you must know the the speed as well as the frequency. The wave speed can be found from the two graphs: the peak that is at x = 0.0 m when t = 0 s is the same one that has moved to x = 0.03 m when t = 0.001 s. This tells us that the wave speed is 0.03 m/0.001 s = 30 m/s. Now the wavelength can be calculated. Note that there is an ambiguity. The peak at (x = 0. t = 0) might not have reached x = 0.03 m until t = 0.005 s. In that case, the speed is 6 m/s. Well ignore this possibility. (This is the stroboscopic effect that makes the wagon wheels in old western movies appear to be rotating backwards.) The wavelength: lambda By choosing the phase, phi, you can slide the graph to the left or right. Find the smallest positive value of phi that correctly describes the above wave.Explanation / Answer
1)
Amplitude is maximum displacement
It is 1.5 mm
2)
Time for 1 wavelength, T = 0.004 s
f = 1/T
= 1/(0.004)
= 250 Hz
3)
v = 30 m/s
wavelength = v/f = 30 / 250 =0.12 m
4)
I seriously dont know this
sorry for it
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