a) To fill a child\'s backyard inflatable wading pool you use a garden hose with
ID: 1481683 • Letter: A
Question
a) To fill a child's backyard inflatable wading pool you use a garden hose with a diameter of 2.9 cm. Water flows from this hose with a speed of 1.3 m/s. How long will it take to fill the pool to a depth of 35 cm if it is circular and has a diameter of 3.9 m?min
b) If there is a section of the hose where the diameter decreases to 1.16 cm, what is the speed of the water in this section?
m/s a) To fill a child's backyard inflatable wading pool you use a garden hose with a diameter of 2.9 cm. Water flows from this hose with a speed of 1.3 m/s. How long will it take to fill the pool to a depth of 35 cm if it is circular and has a diameter of 3.9 m?
min
b) If there is a section of the hose where the diameter decreases to 1.16 cm, what is the speed of the water in this section?
m/s a) To fill a child's backyard inflatable wading pool you use a garden hose with a diameter of 2.9 cm. Water flows from this hose with a speed of 1.3 m/s. How long will it take to fill the pool to a depth of 35 cm if it is circular and has a diameter of 3.9 m?
min
b) If there is a section of the hose where the diameter decreases to 1.16 cm, what is the speed of the water in this section?
m/s a) To fill a child's backyard inflatable wading pool you use a garden hose with a diameter of 2.9 cm. Water flows from this hose with a speed of 1.3 m/s. How long will it take to fill the pool to a depth of 35 cm if it is circular and has a diameter of 3.9 m?
min
b) If there is a section of the hose where the diameter decreases to 1.16 cm, what is the speed of the water in this section?
m/s
Explanation / Answer
R= 3.9m m = 0.0195m , r= 2.9cm/2 = 1.45cm = 0.0145m, h= 35cm = 0.35m , v= 1.3m/s
Volume of water in the pool = rate of volume of water from the pipe*time
V = A*v*t
R^2*h = r^2*v*t
t= (R^2*h)/(r^2*v) = (R^2*h)/(r^2*v) =
t = (3.9^2*0.35)/(0.0145^2*1.3) = 19477s = (19477/60) min = 324min = 5.4 hr
b) r1= 2.9cm/2 = 1.45cm = 0.0145m , r2= 1.16cm/2 = 0.0058m , v1= 1.3 m/s
Use equation of continuity,
A1v1=A2v2 =
v2 = v1*(A1/A2) = v1*[(r1^2)/(r2^2)] = v1*(r1^2/r2^2) = 1.3*(0.0145^2/0.0058^2) = 8.13m/s
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