A welder using a tank of volume 7.70×10 2 m3 fills it with oxygen (with a molar

Question

A welder using a tank of volume 7.70×102 m3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.05×105 Pa and temperature of 39.0 C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 20.8 C, the gauge pressure of the oxygen in the tank is 1.90×105 Pa .

Part A

Find the initial mass of oxygen.

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Part B

Find the mass of oxygen that has leaked out.

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A welder using a tank of volume 7.70×102 m3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.05×105 Pa and temperature of 39.0 C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 20.8 C, the gauge pressure of the oxygen in the tank is 1.90×105 Pa .

Part A

Find the initial mass of oxygen.

m = kg

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Part B

Find the mass of oxygen that has leaked out.

m =   kg

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Explanation / Answer

initial pressure = 101325+3.05×105 Pa

final pressure = 101325+1.90×105 Pa

initially applying ideal gas equation

PV = nRT

(101325+3.05×105) *(7.70×102) = (M/32) 8.3144598* (273+39)

m = 385.945174818 gm

finally

(101325+1.90×105 ) *(7.70×102) = (m/32) 8.3144598* (273+20.8)

m =293.854691854 gm

mass of oxygen that has leaked out. = 385.945174818 gm -293.854691854 gm

=92.090483 gm

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