The intensity of sound is the power of the sound waves divided by the area on wh

Question

The intensity of sound is the power of the sound waves divided by the area on which they are incident. Intensity is measured in watts per square meter, or W/m2.

The human ear can detect a remarkable range of sound intensities. The quietest sound that we can hear has an intensity of 1012W/m2, and we begin to feel pain when the intensity reaches1 W/m2 . Since the intensities that matter to people in everyday life cover a range of 12 orders of magnitude, intensities are usually converted to a logarithmic scale called the sound intensity level , which is measured in decibels (dB). For a given sound intensity I, is found from the equation

=(10dB)log(II0),

where I0=1.0×1012W/m2.

B:

If a speaker gives a sound intensity of106W/m2 at a certain point, what is the sound intensity level at that point?

Express your answer in decibels

Explanation / Answer

here,

the intensity of sound , I = 10^-6 W/m^2

I0 = 10^-12 W/m^2

beta = 10 dB * ( log( I/I0))

beta = 10 dB* log( 10^-6 /10^-12)

beta = 60 dB

the sound intensity level beta at that point is 60 dB

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