A bullet is fired into a block of wood sitting on a block of ice. The bullet has

Question

A bullet is fired into a block of wood sitting on a block of ice. The bullet has an initial velocity of 700m/s and a mass of 0.005 kg. The wooden block has a mass of 1.2kg and is initially at rest. The bullet remains embedded in the block of wood afterward.

a) Assuming that momentum is conserved, find the velocity of the block of wood and bullet after the collision.

b) What is the magnitude of the impulse that acts on the block of wood in this process?

c) Does the change in momentum of hte bullet equal that of the block of wood? Explain.

Explanation / Answer

we use consevation of momentum

initial momentum= final momentum

mbullet * v bullet = ( mblock + m bullet) * v

=>0.005* 700= ( 1.2+0.005)*V

=>V= 2.90 m/s

b) impulse = m * change in velocity = 1.2* ( 0- 2.9) = -3.48 kg m/s

c)c. no, momentum is a vector quality. They are equal in magnitude, but in opposite directions.

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