A person pushes on a stationary 125 N box with 72 N at 30? below the horizontal,

Question

A person pushes on a stationary 125 N box with 72 N at 30? below the horizontal, as shown in the figure. The coefficient of static friction between the box and the horizontal floor is 1.18.(Figure 1)

Part B

What is the normal force on the box?

Part C

What is the friction force on the box?

Express your answer in newtons as an integer.

Part D

What is the largest the friction force could be?

Express your answer in newtons as an integer.

Part E

The person now replaces his push with a 72 N pull at 30? above the horizontal. Find the normal force on the box in this case.

Express your answer in newtons as an integer.

Explanation / Answer

   pushing

   normal force acting is F Sin theta +mg = N
                 

       N = 72*Sin(30) + 125
          = 161 N

friction force on the box is Ff = mue s*N*Cos theta
                                  = 1.18*89*Cos 30
                                  = 90.94 N
                                

D frictional force is largest when the applied force is at 90 degrees only

E if the force is pull above the horizontal

        normal force is = mg - F Sin theta
                                = 250 - 72*Sin 32
                                = 211.84 N

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