Question 4) In humans, Achondroplasia \"dwarfism\" (D) is dominant over normal (

Question

Question 4) In humans, Achondroplasia "dwarfism" (D) is dominant over normal (d). A homozygous dominant (DD) person dies before the age of one. A heterozygous (Dd) person is dwarfed. A homozygous recessive individual is normal. A heterozygous dwarf man marries a dwarf heterozygous woma. What is the probability of having a normal child? What is the probability that the next child will also be normal? What is the probability of having a child that is a dwarf? What is the probability of having a child that dies at one from this disorder?

Explanation / Answer

1. when a heterozygous dwarf man (Dd) marries a dwarf heterozygous woman ( Dd ) the probability of getting a normal child is Dd * Dd = DD ( dwarf child ), Dd ( dwarf child ), dD ( dwarf child) dd ( normal child). out of four child 1 child can be normal child. (1/4)

3. Out of four child three child will be dwarf (3/4)

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