You are playing a game where you drop a coin into a water tank and try to land i

Question

You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this game at fast food places as part of a fundraiser. The sides of the tank are flat and the target is Gin from the side of the tank. Your eye is 9in from the side of the tank. Water has index of refraction of 4/3. If you drop the coin accurately and it falls straight down to the location where the target appears to be, how far are you off? Does the coin fall in front or behind the target as you look at it? Select One of the Following:

Explanation / Answer

let,

object distance u=6 inch

image position is v

refracive index of water n=4/3

use,

n1/u+n2/v=(n2-n1)/R

here,

radius of curvature R is infinite,

n1=4/3 (water)

n2=1 (air)

==>

n1/u+n2/v=(n2-n1)/R

(4/3)/6+1/v=0

====> v=-4.5inches

there fore the coin falls at v'=6-4.5

v'=1.5 inch

here,

coin fall in front of the target

option(d) is correct

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