The PV diagram in the figure below shows a set of thermodynamic processes that m
ID: 1477187 • Letter: T
Question
The PV diagram in the figure below shows a set of thermodynamic processes that make up a cycle ABCDA for a monatomic gas, where AB is an isothermal expansion occurring at a temperature of 370 K. There are 1.95 mol of gas undergoing the cycle with PA = 1.01 ? 106 Pa, PB = 5.25 ? 105 Pa, and PC = 2.02 ? 105 Pa.
(a) Find the volumes VA and VB.
(b) Find the work done in each process of the cycle and the total work done for the whole cycle.
(c) Find the change in thermal energy during the constant-volume process BC.
Explanation / Answer
a)
VA= n*R*TA/PA
=1.95 * 8.314* 370/(1.01*10^6)
= 5.94*10^-3 m^3
VB= n*R*TB/PB
=1.95 * 8.314* 370/(5.25*10^5)
= 1.14*10^-2 m^3
b)
for A-->B
W= n*R*T*ln (PB/PA)
=1.95*8.314*370*ln (5.25*10^5 / (1.01*10^6))
= -3924.9 J
for B--> C
w = -P*delta V
= 0
for C--> D
w = -PC*(VA-VB)
= -2.02*10^5 * (5.94*10^-3 - 1.14*10^-2 )
= 1102.92 J
for D--> A
w = -P*delta V
= 0
c)
Sorry, i dont know this
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