Refer to the graphs on the reverse which were made using a motion detector mount
ID: 1476824 • Letter: R
Question
Refer to the graphs on the reverse which were made using a motion detector mounted above a basketball that was dropped from a height of 1.5 m above the floor. The position measured and indicated is really the position of the top surface of the ball. The velocity graph was computed by the software as the derivative of the position vs. time graph. Complete the following tasks related to this situation.
Describe the motion of the ball at the six indicated times numbered [1] to [6]. That is, describe where it is located and say something about its speed, direction of motion, and acceleration. If you look closely, you should see that at position [3] the ball is still in contact with the floor.
0. 1.0 +10.0t t [sec) 0.5 1.0 001 100L 100 0.5 1.0Explanation / Answer
from 1 ball is released so acceleration is g downwards and some speed in horizontal direction
then ball undergoes free fall with constant acc. and reaches ground . at point 2 it touches ground . since any collision is not instantaneous so it takes some time to get away from ground but its velocity changes from -ve to +ve and so acceleration is much high as acc= del V / T ,(T is much less)
after it looses contact with ground at 3 , it does not have any other force than gravity so again its motion is under constant downward acceleration g and having some initial velocity at some angle (So the path is parabolic) then it goes maximum height due to virtue of its kinetic energy but the at 6 starts going downward because of the force of gravity . In this whole process from 3 to 6 acceleration is constant = g downwards
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