What happened to the current through bulbs A and B as the switch to bulb C was c
ID: 1476316 • Letter: W
Question
What happened to the current through bulbs A and B as the switch to bulb C was closed The current through bulb A increased and current through B decreased. It happened because overall resistance of the circuit decreases so the current through battery (and bulb A) increases. However the voltage across hut A will also increase so the remaining voltage across B (and therefore the Current through B) will reduce. The current through bulbs A and B will not change because adding bulb C does not modify the voltage drop 9and therefore the current) across B. Therefore the remaining voltage drop across A (and the current)The current through bulbs A and B decreased. It happened because after adding an additional bulb the overall resistance of the circuit increased and therefore the current in the circuit will be lower. The current through bulb A decreased and current through B increased. It happened because overall resistance of the circuit Increases so the current through battery (and bulExplanation / Answer
The addition of bulb C to the circuit in between bulbs A and B will make it parallel to both bulbs A and B which are in series. Since all the three bulbs have a common junction, the voltage drops across them are equal. This means the current flows through the bulbs will be same provided they have same resistances.
As the three bulbs are in parallel to each other, the equivalent resistance will decrease. From Ohm's law, the current is voltage drop divided by resistance. Thus, the current flows in the circuit will increase as. This means the current in the three bulbs will increase with equal magnitude.
Therefore, the current through bulbs A and B increased. It happened because overall resistance of the circuit decreased and therefore the current in the circuit will be higher.
Other options are invalid as the current in bulbs A and B are increased equally.
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