As shown in the figure(Figure 2) , a coordinate system with the origin at the eq

Q: As shown in the figure(Figure 2) , a coordinate system with the origin at the eq

Solution: The force on the block at any instant of time is given as, F = - k x where x is the displacement and the minus sign indicates that the force is in opposite direction to the displacement Since F = m a0 = - k A and a0 = - k A / m When the block passes through its equilibrium position F =0 since x = 0 and the acceleration a1 =0

ID: 1476252 • Letter: A

Question

As shown in the figure(Figure 2) , a coordinate system with the origin at the equilibrium position is chosen so that the x coordinate represents the displacement from the equilibrium position. (The positive direction is to the right.)

A) What is the initial acceleration of the block, a0, when the block is released at a distance A from its equilibrium position?

B) What is the acceleration a1 of the block when it passes through its equilibrium position?

Express your answer in terms of some or all of the variables A, m, and k.

Explanation / Answer

Solution:

The force on the block at any instant of time is given as,

F = - k x

where x is the displacement and the minus sign indicates that

the force is in opposite direction to the displacement

Since

F = m a0 = - k A and a0 = - k A / m

When the block passes through its equilibrium position

F =0 since x = 0

and the acceleration

a1 =0

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As shown in the figure(Figure 2) , a coordinate system with the origin at the eq

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As shown in the figure(Figure 2) , a coordinate system with the origin at the eq

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