The tuning circuit in an FM radio receiver is a series RLC circuit with a 0.200

Question

The tuning circuit in an FM radio receiver is a series RLC circuit with a 0.200 H inductor.

1) The receiver is tuned to a station at 105.5 MHz . What is the value of the capacitor in the tuning circuit?

Express your answer to three significant figures.

2) FM radio stations are assigned frequencies every 0.2 MHz, but two nearby stations cannot use adjacent frequencies. What is the maximum resistance the tuning circuit can have if the peak current at a frequency of 105.9 MHz , the closest frequency that can be used by a nearby station, is to be no more than 0.160 % of the peak current at 105.5 MHz ? The radio is still tuned to 105.5 MHz , and you can assume the two stations have equal strength.

Express your answer to two significant figures.

Explanation / Answer

Part 1:
C = 1 / (²L) = 1 / ((2f)2 L) = 1 / (2*3.14*105.5*106)2*0.200*10-6

1.1390*10-11f
C= 11.39pF

Part 2:

0.160/100%
=0.0016 OHMS

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