Lab Exercise sC ND TONICITY PRACTICE PROBLEMs lab exercise, permeable,ell. Like
ID: 147329 • Letter: L
Question
Lab Exercise sC ND TONICITY PRACTICE PROBLEMs lab exercise, permeable,ell. Like is in the solvent water. Water can move into or the plasma membrane, the dialysis tubing is seleet a solute (such as Nac solutions are aqueous solutions, which means i cannot. Whether the water moves into, moves out of, (his model systen environment outside of the "cell"; in bag or model e dialysiss into arnd out of the s out of, or moves into the solution in the beaker surrounding the dialysis bag Carefully read the introduction before completing the pre-lab a good reference for this assignment. Part I: Crvet sim Selectively permeable dialysis bags are used to represent three diier of aqueous cells are placed in beakers, which also contain different aqueous cells placed in three of aques the beakers, answer the questions below. Bcaker #2 The solbotion mode s b) The beaket Beaker # 1 Beaker # 3 c) The solution ins Beaker # 2 d) The sotution e) In which di Cell # 1 Cell # 3 Cell 2 t) Draw Cell # 1 contains 50% NaCl Beaker contains 25% NaCl Cell # 1 contains 15% NaCl Beaker contains 3 g) Exp Cell # 1 contains 30% NaCl Beaker contains 30% NaCl 5% NaCl Beaker#li a) The solution inside the cell contains 50% NaCl and b) The beaker contains 25% NaCl and c) The solution inside cell #1 is % water. % water tonic to the solution outside cell #1 d) The solution outside cell #1 is tonic to the solution inside cell #1 106Explanation / Answer
Beaker #1:
a) The solution inside the cell contains 50% NaCl and 50% water.
Explanation: The cell contains 50% NaCl solution, therefore the cell contains (100-50)% = 50% water.
b) The beaker contains 25% NaCl and 75% water.
Explanation: The beaker contains 25% NaCl solution, therefore the beaker contains (100-25)% = 75% water.
c) The solution inside cell #1 is hypertonic to the solution outside cell #1.
Explanation: A hypertonic solution is considered as a solution that has more solute and less water concentration than another solution. Here, the solution inside cell #1 has 50% NaCl and 50% water while the solution outside cell #1 has 25% NaCl and 75% water. Therefore the solution inside cell #1 is hypertonic to the solution outside cell #1.
d) The solution outside cell #1 is hypotonic to the solution inside cell #1.
Explanation: A hypotonic solution is considered as a solution that has less solute and more water concentration than another solution. Here, the solution inside cell #1 has 50% NaCl and 50% water while the solution outside cell #1 has 25% NaCl and 75% water. Therefore the solution outside cell #1 is hypotonic to the solution inside cell #1.
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