A copper pot with a mass of 0.520 kg contains0.160 kg of water, and both are at

Question

A copper pot with a mass of 0.520 kg contains0.160 kg of water, and both are at a temperature of 23.0 C . A 0.270 kg block of iron at 85.5 C is dropped into the pot.

Part A

Find the final temperature of the system, assuming no heat loss to the surroundings.

A copper pot with a mass of 0.520 kg contains0.160 kg of water, and both are at a temperature of 23.0 C . A 0.270 kg block of iron at 85.5 C is dropped into the pot.

Part A

Find the final temperature of the system, assuming no heat loss to the surroundings.

Explanation / Answer

heat gain by copper pot-water =heat lost by iron

=>Mc*Cpc*(T-23)+Mw*Cpw*(T-23) =Mi*Cpi*(85.5-T)

specific heats: Cpc =0.39kJ/kg, Cpw=4.187kJ/kg, Cpi=0.45kJ/kg

=>0.52*0.39*(T-23)+160*4.187*(T-23)=0.27*0.45*(85.5-T)

=>0.2028T-4.6644+661.92T-15224.16=10.38825-0.1215T

=>662.2443T=15239.05

=>T=23.011oC

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