Lowering a Float A wooden float, of density 700 kg/m3, is 0.600 mlong, 0.300 m w
ID: 1472417 • Letter: L
Question
Lowering a Float
A wooden float, of density 700 kg/m3, is 0.600 mlong, 0.300 m wide, and 0.079 m thick, and floats on the surface of a body of water.
Part A
A lead weight is now attached to the bottom side of the float, sufficient to cause the float's top to be just level with the water's surface. Determine the mass of the lead weight.
Lowering a Float
A wooden float, of density 700 kg/m3, is 0.600 mlong, 0.300 m wide, and 0.079 m thick, and floats on the surface of a body of water.
Part A
A lead weight is now attached to the bottom side of the float, sufficient to cause the float's top to be just level with the water's surface. Determine the mass of the lead weight.
Explanation / Answer
Volume of the displaced water(V)= 0.6*0.3*0.079=0.01422
From archemides principle buyoncy force by water= dVg=1000*0.01422*9.8=139.356 N ;{d-density of water}
Weight of the boat= 700*V*g= 97.5492 N
If the mass of the lead weight is m then for the equillibrium of the boat,
139.356-97.5492-mg=0;
m=4.266 kg
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