A person whose eyes are 1.64 m above the floor stands 2.30 m in front of a verti

Question

A person whose eyes are 1.64 m above the floor stands 2.30 m in front of a vertical plane mirror whose bottom edge is 38 cm above the floor, see the figure(Figure 1) .

Part A

What is the horizontal distance x to the base of the wall supporting the mirror of the nearest point on the floor that can be seen reflected in the mirror?

A person whose eyes are 1.64 m above the floor stands 2.30 m in front of a vertical plane mirror whose bottom edge is 38 cm above the floor, see the figure(Figure 1) .

Part A

What is the horizontal distance x to the base of the wall supporting the mirror of the nearest point on the floor that can be seen reflected in the mirror?

Explanation / Answer

here we know that

Tan (theta) = H - H / L = h/x

( 1.64 m - 0.38 m ) / ( 2.30 m ) = (0.38 m ) / x

we get

x = 0.3936 m = 69.36 cm =================answer)

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