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Firefox File Edit View History Bookmarks Yahoo! Tools Window Help 36% D Sat 4:19

ID: 1472220 • Letter: F

Question

Firefox File Edit View History Bookmarks Yahoo! Tools Window Help 36% D Sat 4:19 PM Sloan Lundberg Phys ity of Memphi PH Chegg c 2018.8 saplinglearning.com/i Feed f CD Pinte Twitter Appl Most Visited Building a Succes book Sapling Learning Organic Chemistry Shark Tracking Yah Google Maps YAHOO The surface tension of a fluid can be measured wit Search Calculator Periodic Table Available From: 11/8/2015 06:00 00 Questi 7 of 27 11/30/2015 06:0 Due Date: Map 00 Late submissions: Allowed with 1 points possibl 00 hough gas station owners lock their tanks at night, a gas station owner in your neighborhood was the victim day until or theft because his employee had a key to the tank 12/10/2015 06 95 matter how no it. H d you as a ctor to dig th he ks. Points Possible 100 What is the minimum depth needed for the surface of the gasoline to be unsiphonable? Grade Category: Graded Assume the specific gravity of gasoline is 0.766. ou can ignore the drop rate of the gasoline level inside the tank 00 Description: Policies: Homework You can check your answers 00 You can view solutions when you co 00 e funds nor approval om the city to dig that up on any question deeply. However, you tell him that the best a thief could hope to have at his disposal is a 202-mbar vacuum pump. Anything better would be enormously expensive. Given this information, how deep would the gasoline You can keep trying to answer each 00 have to sit below e surface to keep it safe om thieves? you get it right or give up You lose 5% of the points available t n your question for each incorrect a answe eTextbook 00 O Help With This Topic Check Answer Next IExit Previous Give Up & V

Explanation / Answer

The lowest pressure that a vacuum pump could ever hope to attain is 0 bar

The height of a column of fluid (assuming the vapour pressure in the tank is 1 bar) then maximally is

Delta(p) = rho g Delta(h)

Delta(h) = Delta(p) / (rho g)
= 10^5 N/m^2 / (766 kg/m^3 * 9.81 m/s^2) = 13.3 meter = 43.63 feet


If Delta(p) is not 1 bar but ( 1 - 0.202 ) bar = 0.798 bar, then the depth needed is reduced by a factor 0.798.

So then

D = 0.798 * 43.6 feet = 34.81 feet

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