a constant torque of 10m•N is applied to the rim of a 8.0-kg uniform disk of rad

Question

a constant torque of 10m•N is applied to the rim of a 8.0-kg uniform disk of radius 0.15m. what is the angular speed of the disk about an axis through its center after it rotates 2.0 revolutions from rest? a constant torque of 10m•N is applied to the rim of a 8.0-kg uniform disk of radius 0.15m. what is the angular speed of the disk about an axis through its center after it rotates 2.0 revolutions from rest? a constant torque of 10m•N is applied to the rim of a 8.0-kg uniform disk of radius 0.15m. what is the angular speed of the disk about an axis through its center after it rotates 2.0 revolutions from rest?

Explanation / Answer

torque = 10 Nm

mass m = 8 kg

radius = 0.15 m

angular displacemet theta = 2 revolution = 2*2*pi rad

work done = change in KE

torque *displacemenet = 0.5*I*(w2^2-w1^2)

10*2*2*pi = 0.5*(1/2)*8*0.15^2*(w2^2-0^2)

w2 = 52.844 rad/s <<----------answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.