T-Mobile 11:46 webassign.net Additional Materials Seton 29 1 The figure below sh

Question

T-Mobile 11:46 webassign.net Additional Materials Seton 29 1 The figure below shows a proton moving at velocity J (-200 m/s)i toward a long straight wire with current i = 360 mA. At the instant shown, the proton's distance from the wire is d = 3.08 cm, what is the magnetic force on the proton due to the current? (Express your answer in vector form.) (-7.48e-23)x N Additional Materials Section 2 A toroid having a square cross section, 3.00 cm on a side, and an inner radius of 11.0 cm has 650 turns and carries a current of 0.700 A (It is made up of a square solenoid bent into a doughnut shape.) (a) What is the magnitude of the magnetic field inside the toroid at the inner radius? (b) What is the magnitude of the magnetic field inside the toroid at the outer radius? Additional Materials Home My Assignments Extension Request

Explanation / Answer

4) given,

I = 360 mA = 0.36 A

d = 3.08 cm = 0.0308 m

v = 200 m/s

mantic field at the location of proton,

B = mue*I/(2*pi*d)

= 4*pi*10^-7*0.36/(2*pi*0.0308)

= 2.34*10^-6 T

magnetic force acting on proton, F = q*v*B*sin(90)

= 1.6*10^-19*200*2.34*10^-6

= 7.49*10^-23 N

direction magnetic force is towards -x axis

so, F = -7.49*10^-23 N i

5) Given N = 650 turns

A = 0.7 A

r_in = 3 cm = 0.03 m

r_out = 11 cm = 0.11 m

a) at inner radius

B_in = mue*N*I/(2*pi*r_in)

= 4*pi*10^-7*650*0.7/(2*pi*0.03)

= 3.03*10^-3 T

at outer surface,

B_out = mue*N*I/(2*pi*r_out)

= 4*pi*10^-7*650*0.7/(2*pi*0.11)

= 8.27*10^-4 T

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.