O 11/22/2015 11:55 PM A 62.1/100 Gradebook Print Calculator Periodic Table Quest
ID: 1470095 • Letter: O
Question
O 11/22/2015 11:55 PM A 62.1/100 Gradebook Print Calculator Periodic Table Question 24 of 29 Map Saping earning You would like to observe an E. coli bacterium that is 2.05 um long. Because diffraction blurs an image. you would like to minimize the effects of diffraction by using a wavelength no larger than the object you are observing. For this problem, assume the wavelength is equal to the length of the bacterium. What is the energy of a photonwith this wavelength? Number What is the energy of an electron with a de Broglie wavelength of this size? Number In terms of energy, which particles, photons or electrons, are the least likely to damage your sensitive biological sample? they are the same O electrons O photons A O Previous Check Answer Next ExtExplanation / Answer
(a)
The energy of a photon is given by the equation
E = hf,
where E is the energy,
h is Planck's constant,
f is frequency
Velocity = Fequency * Wavelength
Fequency = Velocity/Wavelength
E = h*c/
E = (6.626*10^-34) * (3.0 * 10^8) / (2.05 * 10^-6 )
E = 9.69 * 10^-20 J
(b)
= h/p
p = h/
p = (6.626*10^-34) / (2.05 * 10^-6 )
p = 3.232 * 10^-28 Kg m/s
From E=1/2 * m * v^2
2E = m v^2
2Em = (m v)^2
2Em = p^2
E = p^2/ 2*m
E = (3.232 * 10^-28)^2 / (2 * 9.1*10^-31)
E = 5.739 * 10^-26 J
Energy of electron, E = 5.739 * 10^-26 J
(c)
Electrons are least likely to Damage.
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