Motion of a Block with Three Forces Three forces of magnitudes F 1=4.0N , F 2=6.
ID: 1469901 • Letter: M
Question
Motion of a Block with Three Forces
Three forces of magnitudes F1=4.0N , F2=6.0N , and F3=8.0N are applied to a block of mass m=2.0kg , initially at rest, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (net) force by combining the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive).
Part A
Calculate the magnitude of the resultant force Fr=F1+F2+F3 acting on the block.
Express the magnitude of the resultant force in newtons to two significant figures.
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Part B
What angle does Fr make with the positive x axis?
Express your answer in degrees to two significant figures.
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Part C
What is the magnitude of the block's acceleration vector, a ?
Express your answer to two significant figures.
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Part D
What is the direction of a ? In other words, what angle does this vector make with respect to the positive x axis?
Express your answer in degrees to two significant figures.
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Part E
How far (in meters) will the block move in 5.0 s ? Recall that it starts from rest.
Express the distance d in meters to two significant figures.
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Figure 1 of 1
Motion of a Block with Three Forces
Three forces of magnitudes F1=4.0N , F2=6.0N , and F3=8.0N are applied to a block of mass m=2.0kg , initially at rest, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (net) force by combining the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive).
Part A
Calculate the magnitude of the resultant force Fr=F1+F2+F3 acting on the block.
Express the magnitude of the resultant force in newtons to two significant figures.
SubmitHintsMy AnswersGive UpReview Part
Part B
What angle does Fr make with the positive x axis?
Express your answer in degrees to two significant figures.
|Fr| = NSubmitHintsMy AnswersGive UpReview Part
Part C
What is the magnitude of the block's acceleration vector, a ?
Express your answer to two significant figures.
degreesSubmitHintsMy AnswersGive UpReview Part
Part D
What is the direction of a ? In other words, what angle does this vector make with respect to the positive x axis?
Express your answer in degrees to two significant figures.
|a| = m/s2SubmitHintsMy AnswersGive UpReview Part
Part E
How far (in meters) will the block move in 5.0 s ? Recall that it starts from rest.
Express the distance d in meters to two significant figures.
degreesSubmitHintsMy AnswersGive UpReview Part
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d = mFigure 1 of 1
Explanation / Answer
Fx = F1x + F2x + F3x
Fx = (4*cos25)+(6*cos325)-8
Fx = 0.54 N
Fy = F1y + F2y + F3y
Fy = (4*sin25)+(6*sin325)-0
Fy = -1.75 N
F = sqrt(Fx^2+Fy^2) = 1.83 N
+++++++++++
B)
angle = tan^-1(Fy/Fx) = arctan(-1.75/0.54) = 287.15
C)
a = Fnet/m = 0.915 m/s^2
d)
direction = tan^-1(Fy/Fx) = arctan(-1.75/0.54) = 287.15
e)
d = 0.5*a*t^2
d = 0.5*0.915*5^2
d = 11.43 m
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