a sin (Theta dark) = m Lambda where Theta dark = tan\'1 (D/L) Attach a strand of

Q: a sin (Theta dark) = m Lambda where Theta dark = tan'1 (D/L) Attach a strand of

Note- The first part of the question is based on lab work.so try to do it on the lab ,record the data and compute D,L and theta and you get value for a and % error. Second part The diameter of human hair to range from 17 to 181 µm HeNe laser operates at a wavelength of 632.8 nm in the red part of the visible spectrum. Ratio =632.8 nm /181 µm= 632.8*10-9 m/181*10-6m= 0.0035

ID: 1469739 • Letter: A

Question

a sin (Theta dark) = m Lambda where Theta dark = tan'1 (D/L) Attach a strand of hair to the glass holder; the hair should lie vertically along the center of the holder. Tape the ends of the hair to the ends of the holder. Set up the holder so the laser beam strikes the hair and travels to the paper on the opposite wall. Measure D and L. Calculate a, which in this case is the diameter of the hair. Measure a directly with a measuring eyepiece provided by the instructor. L = Theta dark = Lambda = 633 nm = 6.33 x 10^-7 cm Measure slit using eyepiece Percent error = measured - calculated /measured Times 100 % error = What is .he ratio of .he wavelength of helium neon light to the diameter of a human hatr?

Explanation / Answer

Note-

The first part of the question is based on lab work.so try to do it on the lab ,record the data and compute D,L and theta and you get value for a and % error.

Second part

The diameter of human hair to range from 17 to 181 µm

HeNe laser operates at a wavelength of 632.8 nm in the red part of the visible spectrum.

Ratio =632.8 nm /181 µm= 632.8*10-9 m/181*10-6m= 0.0035