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Electrons are accelerated through a voltage difference of 260 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons?
2.60×105 eV

What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)

Explanation / Answer

Final kinetic energy =0.5*m*v^2

2.60*10^5 eV=0.5*m*v^2

2.60*10^5 *1.6*10^-19=0.5*9.1*10^-31*v^2
v^2=0.914*10^22
v=0.956*10^11 m/s
v=0.318*10^3 c
v=3.18*10^2 c

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