Jupiter is orbiting the Sun. What is its angular momentum about the Sun? _______

Question

Jupiter is orbiting the Sun. What is its angular momentum about the Sun?

_____________________ kg x m^2/s

Use the data from the table below to answer the question.

MERCURY VENUS MARS 6 JUPITER EARTH Distance from the Sun (km) (Semi-major axis of orbit) (AU) 57,909,227 0.38709893 108,209,475 0.72333199 6,051.8 149,598,262 1.00000011 227,943,824 1.52366231 778,340,821 5.20336301 69,911 (0.5320 x Earth) (10.9733 x Earth) 1.43128 x 1015 (0.151 x Earth) (1321.337 x Earth) Mean Equatorial Radius (km) 2,439.7 6,371.00 3,389.5 (0.3829 x Earth) (0.9499 x Earth) Volume (km3) 6.08272 x 1010 9.28415 x 1011 1.08321 x 1012 1.63116 x 1011 (0.056 x Earth's) (0.857 x Earth's) 3.3010 x 1023 0.055274 5.427 5.9722 x 1024 1.000000 4.8673 x 1024 6.4169 x 10 1.8981 x 1027 ass (Earth masses) Density (g/cm Equatorial Surface Gravity 0.10744 0.81500 5.243 317.82 1.326 9.80665 40,284 Escape Velocity (km/h) Rotation Period 15.300 58.646 0.2408467 170,503 0.20563593 18,108 216,720 0.41354 11.862615 47,002 0.04838624 37,296 243.018 0.99726968 an Orbit Period (Earth years) Mean Orbit Velocity (km/h) Orbit Eccentricity Orbit Inclination to Ecliptic Inclination of Equator to Orbit 1.0000174 107,218 0.01671123 0.00005 23.4393 0.61519726 126,074 0.00677672 1.8808476 86.677 0.0933941 1.304 0° 177.3 (retrograde rotation) Minimum/Maximum Surface Temperature Major Atmospheric 173/427 min/max 88/58 (min/max Carbon Dioxide, Nitrogen Nitrogen, Oxygen Carbon Dioxide,Hydrogen, Helium Nitrogen, Argon Constituents Moons (or "Natural Satellites") None one 1 moon 2 moons 64 moons 0 0 0 0 es

Explanation / Answer

here,

distance from the sun , d = 778340821 km

radius of the Jupiter , r = 69911 km

mass of sun , ms = 2 * 10^30 kg

mass of jupiter , mj = 1.898 * 10^27 kg *

speed of jupiter in the orbit be v

centripital force = gravitational force

mj*v^2/( r+d) = G*ms*mj/( r+d)^2

v^2 = 6.67 * 10^-11 * 2*10^30/( 778340821000 + 69911000)

v = 13091 m/s

the angular momentum around the sun , L = mj*(r +d)*v

L = 1.898 * 10^27 kg * ( 778340821000 + 69911000) * 13091

L = 1.93 * 10^43 kg.m^2/s

the angular momentum about the sun is 1.93 * 10^43 kg.m^2/s

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