As shown in the figure, a conducting rod with a length of 0.79 m is placed on a
ID: 1467078 • Letter: A
Question
As shown in the figure, a conducting rod with a length of 0.79 m is placed on a horizontal frictionless surface and attached to a power supply by two springs, each with a spring constant of 77 N/m. The springs are initially at their equilibrium length and are in a region where there is a uniform magnetic field of 0.15 T that is perpendicular to the frictionless surface when the power supply supplies a current that causes the wire to move in such a direction that the two springs are stretched.
(a) Determine the stretch of each spring, if the current through the rod is 12 A.
m
(b) Determine the direction of the current through the conducting rod in order for this situation to occur. (Choose your answer with respect to the the orientation of the page.)
bottom to toptop to bottom
Explanation / Answer
A) magnetic force on rod = I ( L X B )
Fm = 12 ( 0.79 x 0.15) = 1.422 N
and Fm = 2kx
1.422 = 2 * 77 * x
x = 9.23 x 10^-3 m
b) you have not provided the figure so its quite difficult tounderstand.
but if field is out of page then ,
using Bcap = Lcap X Bcap
bottom to top
if B is into th epage than.
top to bottom.
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