A 300g bullet is fired horizontally into a 4kg fixed stationary wooden block and

Question

A 300g bullet is fired horizontally into a 4kg fixed stationary wooden block and comes to rest after lodging itself a distance of 15cm into the block.

A.) If the muzzle velocity of the respective rifle is 750 m/s, use principles from conservation of energy including the work done by non-conservative forces to find the average frictional force exerted on the bullet by the wooden block.

B.) If the time it took the bullet to come to a rest inside the wooden block was measured to be 3.2 us (microseconds), how powerful was the rifle in this instance?

Explanation / Answer

change in kinetic energy = work done by friction force

1/2 * mv^2 = F*d

F = mv^2/2d

F = 562500 N

part b )

P = w/t

P = 1/2 * mv^2/t

P = 2.64 x 10^10 J/s

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