1)A 0.33-kg mass is hanging from a spring with spring constant 12 N/m. Then the

Question

1)A 0.33-kg mass is hanging from a spring with spring constant 12 N/m. Then the mass is displaced from the equilibrium by 2.7 cm and let go. What is the resulting frequency not angular frequency of the oscillation?

2)A 0.6-kg mass is hanging from a spring with spring constant 16 N/m. Then the mass is displaced from the equilibrium by 2.2 cm and let go. What is the resulting period of the oscillation?

2)A 0.6-kg mass is hanging from a spring with spring constant 16 N/m. Then the mass is displaced from the equilibrium by 2.2 cm and let go. What is the resulting period of the oscillation?

Explanation / Answer

Here ,

mass , m = 0.33 Kg

spring constant , k = 12 N/m

frequency = sqrt(k/m)/2pi

frequency = sqrt(12/.33)/(6.282)

frequency = 0.96 Hz

the frequency is 0.96 Hz

2)

mass of block , m= 0.6 Kg

spring constant , k = 16 N/m

let the period is T

T = 2pi * sqrt(m/k)

T = 2pi * sqrt(0.6/16)

T = 1.22 s

the resulting period of the oscillation is 1.22 s

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