In a mercury-filled manometer, the open end is inserted into a container of gas

Question

In a mercury-filled manometer, the open end is inserted into a container of gas and the closed end of the tube is evacuated. The difference in the height of the mercury is 80 mm. The radius of the connecting tube is 0.50 cm. Determine the pressure inside the container in newtons per square meter. An identical manometer has a connecting tube that is twice as wide. If the difference in the height of the mercury is the same, then what is the pressure in the container? A liquid manometer contains two liquids. Liquid A on the left side is h meters higher (h

Explanation / Answer

Pressure of the gas P = 80 cm of Hg

We know 76 cm of Hg = 1 atm

               1 cm of Hg = 1 atm / 76

80 cm of Hg = 80 ( 1 atm / 76 )

                  = 1.0526 atm

                 = 1.0526 x1.01x10 5 Pa

                 = 106.3157 x10 3 Pa

                 = 106.3157 x10 3 N/m 2

(b). Pressure doennot depend on radius of the tube.

So, pressure is samei.e., pressure = 80 cm of Hg

                                                   = 1.0526 atm

                                                   = 106.3157 x10 3 N/m 2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.