While placing a compact disc into a CD player, you notice a small chip on it\'s

Question

While placing a compact disc into a CD player, you notice a small chip on it's edge. But you attempt to play the CD anyway by placing the CD into the player's deck with the chip at theta o = 13.9degree as measured from the +x axis. The CD begins to rotate with angular acceleration alpha = 2.31 rad/s^2. If the CD has been spinning for t = 3.51 s and the disc has a radius of r = 6.00 cm, what are the x-y coordinates of the chip after this time, assuming the center of the disc is located at (0.00,0.00). x= cm y= cm

Explanation / Answer

First we are going to find the final angle

f = i + ½**t^2
In this case, i equals 13.9°, which is 0.24 rad, so:
f = 0.24 + ½ *(2.31 rad/s^2)*(3.51 s)^2
f = 14.46 rad
f = 829°
f = 109° with respect to the positive x-axis.

x = 6*cos(180-109) = - 1.953 cm

y = -6*sen(180-109) = 5.673 cm

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