16. How much of your 5M stock do you need to make the final concentration be 50m
ID: 146587 • Letter: 1
Question
16. How much of your 5M stock do you need to make the final concentration be 50mM NaCl
17 how much of a 6x dye do you need to add to a 20ul digest to dilute the loading dye down to 1X?
18.prepare a 2 fold serial dilution series of NaCl to test the effect of different salt concentrationa on plant growth. You want to test 5 dilutions with the most concentrated dilution being 800mM. First calculate how you would prepare 10 ml of a 600ml starting dilution using the 5M NaCl stock.
19. Describe how you would prepare the serial 2 fold dilution series beginning with 800mM. (see below)
20. Prepare a 10 fold series dilution beginning with 5M NaCl and ending with 5mM. Make 10 ml of each dilution. Indicate the volumes of each dilution the concentration, which dilution you are using (see above) and the volume of dH2O.
Explanation / Answer
1. Use the formula C1V1= C2V2
5M X x= 50mM X 100ml
x= 1ml
1ml of 5M NaCl is required to make 100ml of 50mM NaCl.
2. 4ul of 6X loading dye is required for 20ul of sample.
3. Two-fold serial dilution means you are reducing the concentration of a solution by a factor of 2 or you are reducing the original concentration by half. To start with we can prepare the 10 ml of 800mM solution and for that, we need 1.6ml of 5M NaCl and 8.4ml water.
4. B) 400mM 5ml A + 5ml water
C) 200mM 5ml B + 5ml water
D) 100mM 5ml C + 5ml water
E) 50mM 5ml D + 5ml water
5) 10 fold serial dilution decreases the concentration of a given solution by a factor of 10.
A) 5000mM
B) 500mM 1ml A + 9ml water
C) 50mM 1ml B + 9ml water
D) 5mM 1ml C + 9ml water
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