1. In a photoelectric effect experiment light of wavelength 400 nm is used. The
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Question
1. In a photoelectric effect experiment light of wavelength 400 nm is used. The experiment contains a metallic surface with work function of 2.46 eV. What is the maximum kinetic energy of the photoelectrons from this surface?
2. In a photoelectric experiment you are using blue colored light to shine a metallic surface. You increase the intensity of the light. Which one of the following you will observe?
3. A cosmic particle is moving at a speed 0.875c. You measure the particle moves through a distance 799 m. How far does the particle move with respect to its own frame?
no photoelectrons are emitted 2.46 eV 3.30 eV 0.640 eV 0.840 eVExplanation / Answer
1.
Energy, E of photon = hc/(lambda) = [(6.63*10^-34)*(3*10^8)]/(400*10^-9) J = 5.11*10^-19 J or
E = [(5.11/1.6)*(10^-19/10^-19)] eV = 3.1968 eV. So Maximum KE of electron = 3.1968-2.46 = 0.73 eV
2.
C
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