A straight 1.80-m, 152-g wire carries a current in a region where the earth\'s m

Question

A straight 1.80-m, 152-g wire carries a current in a region where the earth's magnetic field is horizontal with a magnitude of 0.550 gauss .

Part A

What is the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it?

Imin =   (A)

Part B

Does the current's value found in part A seem likely that such a wire could support this size of current?

Part C

Show how the wire would have to be oriented relative to the earth's field to be supported in this way?

Explanation / Answer

A) when magnetic force is equal and opposite to weight of the wire, thw ire will flost in air.

Apply, FB = Fg

B*I*L*sin(90) = m*g

I = m*g/(B*L)

= 0.152*9.8/(0.55*10^-4*1.8)

= 15046.5 A

B) No. Beacsue, when this huge current is flowing through wire the wire would melt due to dissipeation of thermal energy.

C) we know, direction of B, South-West

so, the current should flow from west to East

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