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Problem 20.10 A uniform electric field with a magnitude of 5950 N/Cpoints in the

ID: 1463802 • Letter: P

Question

Problem 20.10

A uniform electric field with a magnitude of 5950 N/Cpoints in the positive x direction.

Part A

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive x direction.

Part B

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the negative x direction.

Part C

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive y direction.

Express your answer using one significant figure.

Problem 20.10

A uniform electric field with a magnitude of 5950 N/Cpoints in the positive x direction.

Part A

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive x direction.

U =   J  

Part B

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the negative x direction.

U =   J  

Part C

Find the change in electric potential energy when a +17.0-C
charge is moved 5.00 cm in the positive y direction.

Express your answer using one significant figure.

U =   J  

Explanation / Answer

here,

electric feild , E = 5950 N/C

charge , q = 17 * 10^-6 C

distance moved , d = 5 cm

d = 0.05 m

the change in potential energy , PE = E*q*d

PE = 5950 * 0.05 * 17 * 10^-6

PE = 5.06 *10^-3 J

a) since the positive charge moved in the direction of the field the PE would decrease by 5.06 *10^-3 J

b) charge is moved 5.00 cm in the negative x direction means an increase in PE by 5.06 *10^-3 J


c) motion perpendicular to field so no change in PE

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