(a) A siphon tube is filled with gasoline and closed at each end. One end is ins

Question

(a) A siphon tube is filled with gasoline and closed at each end. One end is inserted into a gasoline tank 0.20 m below the surface of the gasoline. The outlet is placed outsidde the tank at a distance 0.50 m below the surface of the gasoline. The tube has an inner cross-sectional area of 4.4 x 10-4m2. The density of gasoline is 680 kg/m3. Ignoring viscous effects, what is the velocity of the gasoline in the tube shortly after the tube is opened?

(b) What is the corresponding rate of flow of the gasoline?

Explanation / Answer

height =0.20 m

The outlet is placed outside the tank at a distance,h =0.50 m

cross-sectional area = 4.4 x 10-4 m2

The density of gasoline= 680 kg/m3

By Bernoulli's theorem, the equation is

=>P1+1/2dv12 + dgh1 = P2 + 1/2dv22 + dgh2

=>1/2dv2 = dg(h1-h2) [as P1=P2 & v1 = 0,Letv2 = v]

Thus the velocity of gasoline (v) = sqrt[2gh] = sqrt[2 x 9.8 x 0.5]

So,v = 3.13 m/s

Rate of flow = Q = A x v = 4.4 x 10-4 x 3.13 = 1.377 x 10-3 m3/sec

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