Please answer Thanks 1. A researcher would like to perform an experiment in a ze
ID: 1462881 • Letter: P
Question
Please answer Thanks 1. A researcher would like to perform an experiment in a zero magnetic field, which means that the field of the earth must be cancelled. Suppose the experiment is done inside a solenoid of diameter 1.5 m , length 5.0 m, with a total of 7000 turns of wire The solenoid is oriented to produce a field that opposes and exactly cancels the field of the earth. What current is needed in the solenoid's wires? 2. Two particles orbit the earth's magnetic field lines. What is the frequency of the circular orbit for (a) an electron with speed 1.0 x 10^6 m/s? (b) A proton with speed 5.0 x 10^4 m/s? 3. The loop in the figure is being pushed into the 0.20 Tmagnetic field at 50 m/s. The resistance of the loop is 0.30 omega. What is the magnitude and direction of the current in the loop? 4 An electronics hobbyist is building a radio set to receive the AM band, with frequencies from 530 to 1510 kHz . What range variable capacitor will she need to go with a 200 pH inductor?Explanation / Answer
1)
number of turns , N = 7000
length , L = 5 m
let the current in solenoid is I
B = u0*N*I/L
4.5 *10^-5 = u0 * 7000 * I/5
solving for I
I = 0.0256 A
the current in the solenoid is 0.0256 A
2)
earth's magnetic field , B = 4.5 *10^-5 T
a) for the electron ,
frequency = v/(2 * pi * m * v/(B*q))
frequency = B*q/(2*pi*m)
frequency = 4.5 *10^-5 * 1.602 *10^-19/(2*pi*9.109 *10^-31)
frequency = 1.26 *10^6 Hz
b) for the proton ,
frequency = v/(2 * pi * m * v/(B*q))
frequency = B*q/(2*pi*m)
frequency = 4.5 *10^-5 * 1.602 *10^-19/(2*pi*1.67 *10^-27)
frequency = 687.04 Hz
3)
let the current in the loop is I
I = B*v*L/R
I = 0.20 * 50 * 0.05/0.30
I = 1.67 A
the current in the loop is 1.67 A
as the flux is increasing in the loop , the current in the loop is CLOCKWISE
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