1. An air-core solenoid contains 1060 m1 turns of wire per meter and has a cross
ID: 1461974 • Letter: 1
Question
1. An air-core solenoid contains 1060 m1 turns of wire per meter and has a cross-sectional area of 0.159 m2 . A current of 3.2 A is established in the solenoid and is then reduced linearly to zero in 5.77 s. A pickup coil of 50 turns circles the solenoid near its center. What is the magnitude of the induced emf in the pickup coil? Answer in units of V
2. If the resistance of the loop is 0.00401 , what is the induced current? Answer in units of A.
need the answer for both questions please and thank you
Explanation / Answer
magnetic field produced by the solenoid, B = mue*n*I (here n is no of turns on solenoid)
= 4*pi*10^-7*1060*3.2
= 0.00426 T
induced emf in the pickup coil, emf = N*A*dB/dt (here N is no of turns on pickup coil)
= 50*0.159*(0.00426 - 0)/5.77
= 5.87*10^-3 V or 5.87 mV
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.