An ice chest at a beach party contains 12 cans of soda at 2.87 °C. Each can of s

Question

An ice chest at a beach party contains 12 cans of soda at 2.87 °C. Each can of soda has a mass of 0.35 kg and a specific heat capacity of 3800 J/(kg C°). Someone adds a 7.81-kg watermelon at 29.4 °C to the chest. The specific heat capacity of watermelon is nearly the same as that of water. Ignore the specific heat capacity of the chest and determine the final temperature T of the soda and watermelon in degrees Celsius. I have worked this and all I answers have been a no. I don't understand what I did wrong or how to get the correct answer.

Explanation / Answer

specific heat capacity of water= 4181 J/Kg oC
Let the final temperature be T oC
Use:
Heat lost by watermelon = heat gained by cans
m1*C1*delta T1 = m2*C2*delta T2
7.81*4181*(29.4-T) = (12*0.35)*3800*(T-2.87)
960016.134 - 32653.61*T = 15960*T - 45805.2
T= 20.69 oC
Answer: 20.69 oC

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