The image of a crayon appears to be 22.4 cm behind the surface of a convex mirro

Question

The image of a crayon appears to be 22.4 cm behind the surface of a convex mirror and is 1.73 cm tall. The mirror’s focal length is 45.9 cm.

a) How far in front of the mirror is the crayon positioned? Answer in units of cm.

b) Calculate themagnification of the image.

c) Describe the image.

1. virtual, inverted, smaller

2. real, upright, larger

3. real, inverted, larger

4. virtual, upright, smaller

5. real, upright, smaller

6. real, inverted, smaller

7. None of these

8. virtual, inverted, larger

9. virtual, upright, larger

d) How tall is the actual crayon? Answer in units of cm.

Explanation / Answer

image distance = s' = -22.4 cm

height of the image = hi = 1.73

focal length f = -45.9 cm

from lens equation

1/s + 1/s' = 1/f

1/s - 1/22.4 = -1/45.9

object distance = s = 43.75 cm    <<<<,------answer

++++++

(b)

m = -s'/s = 22.4/43.75 = 0.512

(c)

virtual , upright and smaller

OPTION 4

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