You have a resistor of resistance 210 ohms , an inductor of inductance 0.380 H ,

Question

You have a resistor of resistance 210 ohms , an inductor of inductance 0.380 H , a capacitor of capacitance 6.20 microF and a voltage source that has a voltage amplitude of 35.0 V and an angular frequency of 200 rad/s . The resistor, inductor, capacitor, and voltage source are connected to form an L-R-C series circuit.

1)What is the voltage amplitude across the resistor?

2)What is the voltage amplitude across the inductor?

3)What is the voltage amplitudes across the capacitor?

I've already calculated the current amplitude to be 4.61E-2 Amps, and the impedence to be 760 ohms

Explanation / Answer

1

the voltage amplitude across the resistor is

VR = IR =(0.0461 A)(210 ohms) = 9.68 V

2

the voltage amplitude across the inductor is

VL = I*(L) =(0.0461 A)(200 rad/s)(0.380 H) = 3.50 V

3

the voltage amplitudes acros the capacitor is

VC = I/(C) =(0.0461 A)/(200 rad/s)(6.2x10-6)= 37.18 V

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